Fizzbuzz is a classic programming problem, and children’s math game, that is often used in coding interviews. While it’s deceptively simple once you know the answer, it can be quite tricky to implement properly at first. The coding magic that allows you to do so is the modulo operator % which returns the remainder of two numbers as a whole number (IE 6 % 3 = 0 or 4 % 3 = 1).
I’m currently learning Go and this was one of the problems that I had to solve. As I wrote my solution, I realized there are certainly multiple ways to achieve the end result, but my chosen approach was a for loop and conditional statements.
The Problem:
Write a function that prints 1 through 100. If the number is divisible by 3, print fizz. If the number is divisible by 5 print buzz. If the number is divisible by both 3 and 5, print fizzbuzz.
My Solution:
package main
import "fmt"
func fizzbuzz() {
for i := 1; i < 101; i++ {
if i % 15 == 0 {
fmt.Println("fizzbuzz")
} else if i % 3 == 0 {
fmt.Println("fizz")
} else if i % 5 == 0 {
fmt.Println("buzz")
} else {
fmt.Println(i)
}
}
}
func main() {
fizzbuzz()
}Running the Code:
1
2
fizz
4
buzz
fizz
7
8
fizz
buzz
11
fizz
13
14
fizzbuzz
16
17
fizz
19
buzz
fizz
22
23
fizz
buzz
26
fizz
28
29
fizzbuzz
31
32
fizz
34
buzz
fizz
37
38
fizz
buzz
41
fizz
43
44
fizzbuzz
46
47
fizz
49
buzz
fizz
52
53
fizz
buzz
56
fizz
58
59
fizzbuzz
61
62
fizz
64
buzz
fizz
67
68
fizz
buzz
71
fizz
73
74
fizzbuzz
76
77
fizz
79
buzz
fizz
82
83
fizz
buzz
86
fizz
88
89
fizzbuzz
91
92
fizz
94
buzz
fizz
97
98
fizz
buzz